Question

a=3+2√2 ,find the value

Answer 1

(a^6+a^4+a^2+1)/a^3
=a^3+a+1/a+1/a^3
=a^3+1/a^3+a+1/a
=(a+1/a)^3-3(a+1/a)+(a+1/a)
=(a+1/a)[(a+1/a)^2-2]
=[3+2-_/2+1/(3+2-_/2)][{3+2-_/2+1/(3+2-_/2)}^2-2]
=(3+2-_/2+3-2-_/2)[{3+2-_/2+3-2-_/2}^2-2]
=6[(6^2)-2]
=6×34
=344

Answer 2

the solution is 344..