Question

A=3+2✓2 then the value of a^1/2+a^-1/2 can foundation

Answer 1

Answer is
$2 \sqrt{2}$

Answer 2

(3+2√2)½+(3+2√2)-½
(3+2√2)½+(1/3+2√2)½
(3+2√2)½+(3-2√2)½
(2+1+2√2)½+(2+1-2√2)½
[√2²+1²+2(√2)(1)]½+[√2²+1²-2(√2)(1)]½
[(√2+1)²]½+[(√2-1)²]½
(√2+1)+(√2-1)
√2+1+√2-1
=2√2
or
(1+2+2√2)½+(1+2-2√2)½
[1²+√2²+2(1)(√2)]½+[1²+√2²-2(1)(√2)]½
[(1+√2)²]½+[(1-√2)²]½
1+√2+1-√2
=2