Question

a=✓3-✓2/✓3+✓2 , b=✓3+✓2/✓3-✓2 find the value of a^2+b^2-5ab

Answer 1

A = (√3-√2)/(√3+√2)
  = (√3-√2)/(√3+√2)× (√3-√2)/(√3-√2) [ rationalizing it]
  =(√3 -√2)²/1 = (√3 -√2)² = 5- 2√6
b= (√3+√2)/(√3-√2)×(√3+√2)/(√3+√2) [ rationalizing it]
 = (√3+√2)²/1 =(√3+√2)² = 5+2√6
now, a²+b² - 5ab 
= (5-2√6)² + (5+2√6)² - 5(5-2√6)(5+2√6)
=25 +24 -20√6 +25 +24 + 20√6 - 5(25-24)
=98 -5 = 93

Answer 2

this is the answer of your question