Question

a = √3 + √2 and b= √3-√2 find the value of

a² + b ^2​

Answer 1

Step-by-step explanation:

GIVEN

a=√3+√2

b=√3-√2

then,

a²+b²

=(√3+√2)²+(√3-√2)²

=(√3)²+(√2)²+2√6+(√3)²+(√2)²-2√6

=3+2+2√6+3+2-2√6

=5+5

=10

since value of a²+b² is 10

hope this helps you

Answer 2

Answer:

10

Step-by-step explanation:

a = √3 +√2

b= √3 -√2

a² + b²= (√3+√2)² + (√3-√2)²

a² +b² = {(√3)² + (√2)² + 2(√3 ×√2)} + {(√3)²+(√2)²- 2(√3 × √2)}

a²+b²= 3+2+2√6 + 3+2-2√6

a²+b²= 10