Question

A(-3,2) b(3,2) c(-3,-2) are the vertices of the right angle at a show that mid point of the hypotenuse is equidistant from the vertices

Answer 1

Step-by-step explanation:

Formula used:

Midpoint formula:

The midpoint of the line joining

Distance formula:

The distance between two points

Let S be the midpoint of hypotenuse BC.

Then, S is

(0,0)

Now,

This implies

SA=SB=SC

Hence S is equidistant from A, B and C