(a-3)^2+(b-4)^2+(c-9)^2=0
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Answer is - a=3,b=4,c=9
As we know that if the sum of square of real numbers equals to zero then the real numbers are individually becomes zero.
So, here we can say -
a-3=0 therefore a=3
b-4=0 therefore b=4
c-9=0 therefore c=9
As we know that if the sum of square of real numbers equals to zero then the real numbers are individually becomes zero.
So, here we can say -
a-3=0 therefore a=3
b-4=0 therefore b=4
c-9=0 therefore c=9
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