Question

A(3,2) B(7,4). Find C so that ABC is an equilateral triangle. Plz solve this question by parametric form.

Answer 1

Answer:

Let an equilateral triangle Δ ABC : AB = BC = AC.

 vertices are A(3,2) and B(-3,2) and C(x,y).

The mid point of the side AB is M (0,2).

 (AB)² =  (3+3)² + (2-2)² = 6² + 0² = 36 

AB = 6 cm

AB = BC = AC = 6 unit.

AM = 3 unit.

As two vertices are A(-3,2) and B(3,0) so that Third vertex will be at

Y-axis(x=0).

so that

Third vertex C(0,y) and it is located below the origin.

Hence it contains the origin.

Now,

because it is an equaletral triangle i use distance formula here to solve the problem

Step-by-step explanation:

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Answer 2

Answer:

$am = 3unit$