Question

a) 3
2. Let a=7,d=3 ,n=8,then the value of a n is
a)25
b)27
c)20
d)28​

Answer 1

$\huge{\blue{\boxed{\green{\underline{\orange{\mathbb{Question✩}}}}}}}$

a=7, d=3, n=8 find an term of A.P

a)25

b)27

c)20

d)28

$\bold{\huge\pink{\boxed{{{Answer (d)➺ 28}}}}}$

STEP BY STEP SOLUTION :-

$\huge \mathcal \color{maroon}{Given :-}$

$\\ a \: = 7 \\ d = 3 \: \: \\ n = 8 \:$

$\huge \mathcal \color{maroon}{To \: find :-}$

${}^{a}n = ?$

$\huge \mathcal \color{maroon}{Solution :-}$

${}^{a} n = a + (n - 1)d \\ (by \: putting \: the \: value \: of \: a,d \: and \: n) \\ ⟹7 + (8 - 1)3 \\ ⟹7 + (7 \times 3) \\ ⟹7 + 21 \: \: \: \: \: \: \\ ⟹an=28 \: \: \: \: \: \: \: \: \: \:$

$\huge \mathcal \color{maroon}{Information :- }$

$Here, \: \\ \: \: ➯ \: a=1st \: term \: of \: \: AP \\ ➯ \: d = common \: diffrence \\ ➯ \: n = number \: of \: terms \\ ➯ \: {}^{a} n = last \: term \\ ➯ \: formula \: used = a + (n - 1)d$

Answer 2

Answer

$\huge\mathcal{Given:}$

• a=7
• d=3
• n=8

$\huge \mathcal {To \: find :-}$$a_n$

$\huge \mathcal {Solution :-}$$a_n=a+ (n - 1) d$

(by putting the value of a,d, a_n )

⟹7+(8−1)3

⟹7+(7×3)

⟹7+21

$⟹a_n=28$