Math, asked by anilamuley098, 8 months ago

a^3 + 3a ^2 + 9a = 1 then a^3 + 3/a=?​

Answers

Answered by priyanandani7002
1

Answer:

28

Step-by-step explanation:

Here, the given equation is,

a^3+3a^2+9a=1a

3

+3a

2

+9a=1 ------ (1)

3a\times (a^3+3a^2+9a)=33a×(a

3

+3a

2

+9a)=3

3a^4+9a^3+27a^2=3a3a

4

+9a

3

+27a

2

=3a

3a^4+9(a^3+3a^2)=3a3a

4

+9(a

3

+3a

2

)=3a

By the equation (1)

3a^4+9(1-9a)=3a3a

4

+9(1−9a)=3a

3a^4+9-81a=3a3a

4

+9−81a=3a

3a^4+9 = 84a3a

4

+9=84a

By dividing each term by 3a,

a^3+\frac{3}{a}=28a

3

+

a

3

=28

Hence, the required answer is 28.

Answered by Sagarmuddada123
0

Answer:

817 is the answerit may help you

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