a^3-3a^2b+3ab^2-b^3 =
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Solution
a3−3a2b+3ab2−b3
(a−b)3=a3−b3−3ab(a−b)
⇒a3−b3−3a2b+3ab2
Compairing both polynomials we get,
∴a3−3a2b+3ab2−b3=(a−b)3
Answered by
0
Answer:
( a-b)^3
Step-by-step explanation:
a^3-3a^2b+3ab^2-b^3 = ( a+b)^3
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