Math, asked by harineemathevan, 9 days ago

a^3-3a^2b+3ab^2-b^3 =




Answers

Answered by dbsivamani
2

Solution

a3−3a2b+3ab2−b3

(a−b)3=a3−b3−3ab(a−b)

⇒a3−b3−3a2b+3ab2

Compairing  both polynomials we get,

∴a3−3a2b+3ab2−b3=(a−b)3

Answered by angshukiranghosh
0

Answer:

( a-b)^3

Step-by-step explanation:

a^3-3a^2b+3ab^2-b^3 = ( a+b)^3

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