a^3+3a^2b+3ab^2+b^3-8
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Answer:
a³ + 3a²b + 3ab²+ b³ - 8
= ( a + b )³ - 2³
= ( a + b - 2 )[(a+b)² + (a+b)2 + 2² ]
= ( a + b - 2 ) [ a²+2ab+b² +2a + 2b + 4]
= ( a + b - 2 ) ( a² + b²+2ab + 2a+2b+4)
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