(a^3+3ab^2)/(3a^2+b^3) = (x^3+3xy^2)/3x^2y+y^3)
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Answer:
hope it helps. please mark me as BRAINLIEST
Step-by-step explanation:
Applying componendo and dividendo,
(a−b)
3
(a+b)
3
=
(x−y)
3
(x+y)
3
⇒
a−b
a+b
=
x−y
x+y
⇒
b
a
=
y
x
⇒ay=bx.
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