Math, asked by Dibi3732, 5 days ago

(a^3+3ab^2)/(3a^2+b^3) = (x^3+3xy^2)/3x^2y+y^3)

Answers

Answered by suhani246868
0

Answer:

hope it helps. please mark me as BRAINLIEST

Step-by-step explanation:

Applying componendo and dividendo,

(a−b)

3

(a+b)

3

=

(x−y)

3

(x+y)

3

a−b

a+b

=

x−y

x+y

b

a

=

y

x

⇒ay=bx.

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