Math, asked by mahajanudit200618, 24 days ago

(a/3-3b)(a^2/9+ab+9b^2)​

Answers

Answered by devananda2025
0

Answer:

(a/3-3b)(a^2/9+ab+9b^2)

a/3×a^2/9+a/3×ab+a/3×9b^2-3b×a^2/9-3b×ab-3b×9b^2

a^3/27+a^2b/3+9ab^2/3-3a^2b/9-3ab^2-27b^3

=a^3/27-27b^3

Step-by-step explanation:

hope it helps!!

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