Question

(a^3)^4×{a÷(a^2)^2}​

Answer 1

Answer:

AB=

(3−2)

2

+(4+1)

2

=

1+25

=

26

BC=

(−2−3)

2

+(3−4)

2

=

25+1

=

26

CD=

(−3+2)

2

+(−2−3)

2

=

1+25

=

26

DA=

(−3−2)

2

+(−2+1)

2

=

25+1

=

26

AC=

(−2−2)

2

+(3+1)

2

=

16+16

=

32

BD=

(−3−3)

2

+(−2−4)

2

=

36+36

=

72

Now we can see that

AB=BC=CD=DA=

26

units but daigonals AC



=BD

=> ABCD is a quadrilateral whose all sides are equal but diagonals are not equal.

=> ABCD is a rhombus, not a square.

Area of rhombus ABCD =

2

1

× (Product of diagonals)

=

2

1

×(AC×BD)

=

2

1

×(

3

2×

7

2)

=24 sq.units

Answer 2

$\huge \tt = > {( {a}^{3} )}^{4} \times \frac{a}{ {( {a}^{2} )}^{2} } \\ \\ \huge \tt = > {a}^{12} \times \frac{a}{ {a}^{4} } \\ \\ \huge \tt = > \frac{ {a}^{(12 + 1)} }{ {a}^{4} } \\ \\ \huge \tt = > \frac{ {a}^{13} }{ {a}^{4} } \\ \\ \huge \tt = > {a}^{(13 - 4)} \\ \\ \huge \tt = > {a}^{9}$