A(-3, -4), B(-5, 0), C(3, 0) are the vertices of ∆ABC. Find the co-ordinates of the circumcentre of
∆ABC.
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Answer:
By using area of triangle formula: 1/2[X1(y2-y3)+X2(y3-y1)+X3(y1-y2)]
Step-by-step explanation:
1/2[(-3)(0-(-4))+(-5)(0-(-4))+3(-4-0)]
1/2(-3×4)+(20)+{3×(-4)}
1/2{-12+20+(-12)}
1/2(-4)
=-2
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