Question

(a) 3
4. The zeroes of the polynomial f(x) = 4x² – 12x + 9 are:
(a) 3/2, 3/2
(b) 3/2,-3/2
(c) 3,4
(d) -3, -4
5. If p(x) is a polynomial of at least degree one and p(k) = 0, then k is known as
(a) value of p(x)
(b) zero of p(x)
(c) constant term of p(x)
(d) none of these
6. If p(x) = ax + b, then zero of p(x)
(a) a
(b) b
(c) - a/b
(d) -b/a​

Answer 1

Answer:

4)By the factorization we can find the zeroes

-6and another - 6 gives the product 36 and gives the sum - 12

So x=6/4 =3/2

a) 3/2,3/2

5) 0 is the remainder. So k completely divides the polynomial. Therefore k is rhe zero of the polynomial

b) zero of p(x)

6) let we assume p(x) =0

ax+b=0

ax=-b

X=-b/a

d)-b/a

Answer 2

Answer:

the answer of first question is option (a)

Step-by-step explanation:

second answer is option (b)

third answer is option (d)