Question

a. 3+(4x5)=3+ ……= ………

b. 17-(35÷5) =17 - ……..= …..

c. (7x3) –(2x4) = ……. - …… = ……

d. (7 – 4) X 12 = ……. X ……. = ……

e. 2.5 –(0.7 X2) = ……

f. 78 ÷ (3.75 X 8) = ……

g. 5X2 + ( 37 + 3 X5) + 37 =

h. (18 -7) + 20 – 8 + 24 X 1 =​

Answer 1

Answer:

a. 3+(4x5)=3+ …20…= ……23…

b. 17-(35÷5) =17 - …7…..= …10..

c. (7x3) –(2x4) = …21…. - …8… = …13…

d. (7 – 4) X 12 = …3…. X …12…. = …36…

e. 2.5 –(0.7 X2) = 2.5-1.4=1.1

f. 78 ÷ (3.75 X 8) = 78÷30=2.6

g. 5X2 + ( 37 + 3 X5) + 37 = 10+52+37=99

h. (18 -7) + 20 – 8 + 24 X 1 = 11+20-8+24=47

Answer 2

☑️ To Find :

• Required values.

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☑️ By Using :

• BODMAS RULE

$\bigstar \: B = Bracket$

$\bigstar \: O = Of$

$\bigstar \: D = Divide$

$\bigstar \: M = Multiply$

$\bigstar \: A = Addition$

$\bigstar \: S = Subtraction$

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$\large{\{\purple{\boxed{\boxed{\mathfrak{\underline{\underline{\pink{\bigstar{.SoLuTioNs.}}}}}}}}}$

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(a) 3 + (4 × 5) = 3 + 20 = 23

(b) 17 - (35 ÷ 5) =17 - 7 = 10

(c) (7 x 3) – (2 x 4) = 21 - 8 = 13

(d) (7 – 4) × 12 = 3 × 12 = 36

(e) 2.5 – (0.7 × 2) = 2.5 - 1.4 = 1.1

(f) 78 ÷ (3.75 × 8) = 78 ÷ 30 = 2.6

(g) 5 × 2 + ( 37 + 3 × 5) + 37

= 10 + (37 + 15) + 37

= 47 + 52 = 99

(h) (18 - 7) + 20 – 8 + 24 × 1

= 11 + 20 - 8 + 24

= 55 - 8 = 47

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⋰ Hope It Will Be Helpful To You Mate ⋱

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