A 3.7 g sample of copper(II) carbonate is added to 25 cm^3 of 2.0 mol dm^-3 hydrochloric acid. Which volume of gas is produce under room conditions?
A. 0.60 dm^-3
B. 0.72 dm^-3
C. 1.20 dm^-3
D. 2.40 dm^-3
Please help, I keep getting the answer as B but it’s wrong.
Answers
Answered by
3
Answer:
1.1 g CO2 should be produced from your reaction.Now convert this mass to volume according your room temperature
Answered by
11
Answer: A.0.60 dm^3
Explanation: CuCO3 + 2HCl 一> CuCl2 + CO2 + H2O
nHCl= C×V = 25 × 10^-3 × 2 = 0.05 mol
nCO2 = 1/2 × 0.05 = 0.25 mol
VCO2 = n × 24 = 0.25 × 24 = 0.60 dm^3
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