((a ^ (3 - 7a) * a ^ (6 - 2a))/(a ^ (2a) * a ^ (9 - 2a))) ^ (1/9)
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That's the answer,hope it solved your quarries!!!
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Answer: a⁻ᵃ
Step-by-step explanation:
Since the base is same, the powers can be added when in multiplication and subtracted when in division.
First we solve the numerator and denominator separately by adding the powers
(a³⁻⁷ᵃ⁺⁶⁻²ᵃ/ a²ᵃ⁺⁹⁻²ᵃ)^1/9
=(a⁹⁻⁹ᵃ/a⁹)^1/9
Now since numerator and denominator are in division we have to subtract the powers
=(a⁹⁻⁹ᵃ⁻⁹)^1/9
=(a⁻⁹ᵃ)^1/9 =a^-9a x 1/9
=a^-a
Therefore the answer is a⁻ᵃ
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