Question

a ^3=81,b^3=72 find ab

please step by step btana urgent hai​

Answer 1

${a}^{3} = 81 \implies a = \sqrt[3]{ {3}^{4} }$

$\implies a = 3\sqrt[3]{3}$

And

${b}^{3} = 72 \implies b = \sqrt[3]{2^{3} \times 9 }$

$= 2\sqrt[3]{9 }$

$\implies a\times b= 3\sqrt[3]{3}\times 2\sqrt[3]{9 }$

$= 6\sqrt[3]{3}\times \sqrt[3]{3\times 3 }$

$= 6\sqrt[3]{3}\times\sqrt[3]{3}\times\sqrt[3]{3}$

$= 6\times 3 = 18$