Question

a^3-8b^3+64c^3+24abc Factorise

Answer 1

Here's your answer!!
_________________

See the attachment !!

_________________

Hope it helps you!! :)

Answer 2

Factorise :

         a³ - 8b³ + 64c³ + 24abc

By using Identity VIII : x³  y³  z³ - 3xyz = (x + y + z)(x² + y² + z² - xy - yz - zx)

Here, we have

     a³ - 8b³ + 64c³ + 24abc

                   = a³ + (-2b)³ + (4c)³ - 3(a)(-8b)(4c)

                   = [a + (-8b) + 4c][a² + (-2b)² + (4c)² - (a)(-2b) - (-2b)(4c) - (4c)(a)]

               ⇒ (a - 8b + 4c)(a² + 4b² + 16c² + 2ab + 8bc - 4ac)

HOPE IT HELPS ...