a^3+8b^3-c^3+6abc
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1
Answer:
Hey mate!
Step-by-step explanation:
a^{3}a
3
+ b^{3}b
3
+ 8c^{3}8c
3
- 6abc
= (a)^{3}(a)
3
+ b^{3}b
3
+ (2c)^{3}(2c)
3
- 3(a * b * 2c)
= ( a + b + c) {a^{2}a
2
+ b^{2}b
2
+ (2c)^{2}(2c)
2
- ab - 2bc - 2ca}
= (a + b+ c) ( a^{2}a
2
+ b^{2}b
2
+ 4c^{2}4c
2
- ab - 2bc - 2ca)
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