A 3.91 μF capacitor and a 7.41 μF capacitor are connected in series across a 12.0 V battery. What voltage would be required to charge a parallel combination of the same two capacitors to the same total energy?
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As we know q=cv
In series case
Q=(c1c2/c1+c2) v
Q=(3.91*7.41/3.91+7.41)12
Q=31.2c
As all are same
Parallel case
31.2=(c1+c2)v
31.2=11.32*v
V=31.2/11.32
V=2.7V(approx)
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