Question

(a^3+a^-2)(a^2-3a)=a^5+pa^4-3/a+q. Find the respective values of q and p.

Answer 1

Answer:P=-3 & Q=1

Step-by-step explanation:

By multiplying the above bracket

We get a^5-3a^4-3/a+1

Comparing with given equation we get value of p and q.

Answer 2

Answer:

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Step-by-step explanation:

BY MULTIPLYING THE ABOVE BRACKET

WE GET

$\frac{ {a}^{5} - {3a}^{4 - 3}}{a + 1}$

comparing with given equation we get

Q=1 P=-3

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