( a+ 3)(a-3)-a (a+5)=6
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(a+3)(a-3)-a(a+5)=6
We have an identity,
=>(a+b)(a-b)=a²-b²
Now,
=>(a)²-(3)²-a(a+5)=6
=>a²-9-a²-5a=6
Rearranging the like terms,
=>a²-a²-5a= 6+9
=> 0-5a= 15
=> -5a= 15
=> -a= 15÷5
=> a= -3
Answer: a= -3
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