Question

a-3, a-5, a-7,....... AP​

Answer 1

Answer:

it's Ap series answer is convrgent

Answer 2

Answer:

You didn't ask the question that what we have to do, but let's find three more terms.

$a_{4}$= -5a-9, $a_{5}$= -7a-11 and $a_{6}$= -9a-13

Step-by-step explanation:

AP: a-3,a-5,a-7...

a= a-3

$d_{1}$= $a_{2}-a_{1}$             $d_{2}$= $a_{3}- a_{2}$

$d_{1}$=a-5-(a-3)           $d_{2}$=a-7-(a-5)

$d_{1}$=a-5-a+3            $d_{2}$=a-7-a+5

$d_{1}$= -2                    $d_{2}$= -2

Yes, its an AP.

$a_{4}$= a+3d                $a_{5}$= a+4d               $a_{6}$= a+5d

  = a-3+3(-2)            = a-3+4(-2)             = a-3+5(-2)

  = a-3-6                  = a-3-8                   = a-3-10

  = a-9                     = a-11                      = a-13

So, the other three terms are a-9, a-11 and a-13.

HOPE IT HELPS (n_n)