Question

(a/3-b/2)² expand pls​

Answer 1

Answer:

$(a-b)^{2}$= $a^{2} +b^{2} - 2ab$

  $[a/3-b/2]^{2} = [a/3]^{2} +[b/2]^{2} -2[a/3][b/2]\\ =a^{2}/9+b^{2}/4-ab/6$

  $4a^{2}/36+9^{2}/36-6ab/36$