Question

a=3 b=2 c=4 then value 3ab-2a(b)^+4abc is

Answer 1

Step-by-step explanation:

$a = 3 \\ b = 2 \\ c = 4 \\ \\ 3ab - 2a {b}^{2} + 4abc \\ = 3(3)(2) - 2(3) {(2)}^{2} + 4(3)(2)(4) \\ = 18 - (6 \times 4) + 96 \\ = 18 - 24 + 96 \\ = \underline{ \underline{90}}$