Question

a=3 b=2 find ab+ba aa+bb​

Answer 1

Answer:

1 st type -:

1. 12

2. 13

2 nd type -:

1. 64

Step-by-step explanation:

First this question is not clear because there is not given that there is two question or one question. So I will make it in 2 types .

1 st :

I will make it as a one question

2 nd :

I will make it in the 2 question.

Given :

a = 3

b = 2

Concept :

If there will be no sign given then multiply the value .

Solution :

1 st type -:

So , there are two question -:

1. ab+ba

2. aa+bb

1 -:

A/Q , a = 3 ; b = 2

$:\implies\sf{3\times2+2\times3}$

$:\implies\sf{6+6}$

$:\implies\sf{12}$

So , the value of number 1 is 12 .

2 -:

$:\implies\sf{3\times3+2\times2}$

$:\implies\sf{9+4}$

$:\implies\sf{13}$

So , the value of number 2 is 13 .

2 nd type -:

So , it make it as one question .

1. ab+baaa+bb

$:\implies\sf{3\times2+2\times3\times3\times3+2\times2}$

$:\implies\sf{6+54+4}$

$:\implies\sf{64}$

So , the value of the question is 64 .

Answer 2

Answer:

Here it is

Step-by-step explanation:

Given,  a=3

            b=2

ab+ba+aa+bb

(3×2)+(2×3)+(3×3)+(2×2)

6+6+9+4

25

Hope it helps you