Question

a = 3, b =2 find the value of
$a^{b} +b^{a} +a^{a} +b^{b}$

Answer 1

Answer:

48

Step-by-step explanation:

Given a=3,b=2

∴ a^b +  b^ a +  a^a +  b^b

= 3^2 + 2^3 + 3^3 + 2^2

= 9  + 8 + 27+ 4

= 48

Answer 2

Answer:

your answer is 40.

Step-by-step explanation:

Q. a^b+b^a+a^a+b^b

Ans. a=3,b=2

a^b+b^a+a^a+b^b

=3^2+2^3+3^3+2^2

=3×3+2×2×2+3×3×3+2×2

=3+8+27+2

=40

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