a^3–b^3+1+3ab factorise
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Step-by-step explanation:
using identity :
a³-b³=(a-b)(a²+b²+ab) (a+b)²=a²+b²+2ab
(a-b)(a²+b²+ab)+1+3ab
(a-b)(a+b)²+1+4ab.
(a-b)a²+b²+2ab+1+4ab
(a-b)(a+b)(a+b)+6ab+1
a²-b²(a+b)+6ab+1
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(a+b)^3
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