Question

a^3 + b^3 + 3ab^2 + 3a^2b
if a=2, b= -3​

Answer 1

Answer:

Now, substituting the value of у in x + 2y, -2(a2- ab+b2) b-2a dx2 ~ b2 2 \a2b - ab2 + b3 - 2a3 + 2ab2 - 2ab2] [b-2a] 3b x - 2e3 + 3a2b - 3ab2] [-(a3 - 3a2b + 3ab2 -b3) - b3] 3b x Л — If b x a, ...

Step-by-step explanation:

Hope it will help you. Have a great day.

Answer 2

Answer:

after substituting the values-

2^3 + (-3)^3 + 3(2* -3)^2 + 3 (2^2 * -3)

=2^3 - 3^3 + 3(2* -3)^2 + 3 (2^2 * -3)

=8 - 27 + 3(-6)^2 + 3(-12)

= 8- 27 - 108 - 36

solve the last step :)

Step-by-step explanation:

hope it helps:)

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