(a ^ 3 + b ^ 3)/(a ^ 2 + 2ab + b ^ 2) ÷ 63 (a ^ 2 - b ^ 2)/(a - b)
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Answer:
(
x
b
x
a
)
a
2
+ab+b
2
×(
x
c
x
b
)
b
2
+bc+c
2
×(
x
a
x
c
)
c
2
+ca+a
2
=(x
a−b
)
a
2
+ab+b
2
×(x
b−c
)
b
2
+bc+c
2
×(x
c−a
)
c
2
+ca+a
2
=x
a
3
+a
2
b+ab
2
−a
2
b−ab
2
−b
3
×x
b
3
+b
2
c+bc
2
−cb
2
−bc
2
−c
3
×x
c
3
+c
2
a+ca
2
−c
2
a−ca
2
−a
3
=x
a
3
−b
3
×x
b
3
−c
3
×x
c
3
−a
3
=x
a
3
−b
3
+b
3
−c
3
+c
3
−a
3
=x
0
=1 [henceproved]
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