a^3+b^3= (a+b)^3-3ab(a+b) kindly proof it
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a^3+b^3=(a+b)^3-3ab(a+b)
a^3+b^3=a^3+b^3+3×a×b(a+b)-3ab(a+b)
a^3+b^3=a^3+b^3+3ab(a+b)-3ab(a+b)
a^3+b^3=a^3+b^3
hence proved
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