Question

a^3+b^3=(a-b) (a^2+ab+b^2)​

Answer 1

Answer:

(a-b)(a²+ab+b²)

= a(a²+ab+b²) -b(a²+ab+b²)

=a³+ a²b+ ab²- a²b- ab²- b³

=(a³-b³) + (a² b -a²b) + (ab²- ab²)

=a³-b³ + 0+ 0

=a³-b³

(a-b)(a²+ab+b²)= a³-b³

Hence, proved.

Step-by-step explanation:

Answer 2

Answer:

It is equal

Step-by-step explanation:

$a^3+b^3=(a+b) (a^2-ab+b^2)$

$a^{3}+ b^{3}=(a^{3} +a^{2} b+ab^{2}-a^{2}b-ab^{2}+b^{3})$

After cancelling $a^{2}b$ and $ab^{2}$ with each other.

We get,

$a^{3} +b^{3} = (a^{3} +b^{3})$

P.S. U seem to have messed up the sign in the question. As for the formula $a^{3}+ b^{3}$ it will be (a+b) as it is positive and for $a^{3} -b^{3}$ it would be (a-b). If ur question is $a^{3} -b^{3}$ then the steps would be the same as above just change the signs.

Hope it helps :)