a^3-b^3-a+b factorize
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Hey mate here is your answer.
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Step-by-step explanation:
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We know the identity a^3-b^3=(a-b)(a^2+b^2+ab),
Using the above identity, the equation a^3-b^3-a+b can be factorised as follows:
⇒a^3-b^3-a+b,
⇒(a^3-b^3)-(a-b),
⇒{(a-b)[a^2+b^2+a*b]}-(a-b),
⇒[(a-b)(a^2+b^2+ab)]-(a-b),
⇒(a-b)(a^2+b^2+ab-1),
Hence,a^3-b^3-a+b is (a-b)(a^2+b^2+ab-1).✔✔✔✔✔
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Hope it helps you.
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