Question

(a^3+b^3+c^3 -3abc) ÷ (a+b+c)​

Answer 1

Answer:

a^2+b^2+c^2 -ab-bc-ca

Step-by-step explanation:

a^3+b^3+c^3 -3abc=(a+b+c)(a^2+b^2+c^2 -ab -bc-ca)

(a^3+b^3+c^3 -3abc) ÷ (a+b+c)

(a+b+c)(a^2+b^2+c^2 -ab -bc-ca)÷(a+b+c)

(a^2+b^2+c^2 -ab -bc-ca)

Answer 2

Answer:

=a²+b²+c²-ab-bc-ca

Step-by-step explanation:

a^3+b^3+c^3 -3abc=(a+b+c)( a²+b²+c²-ab-bc-ca)

so  (a^3+b^3+c^3 -3abc) ÷ (a+b+c)​

=(a^3+b^3+c^3 -3abc) / (a+b+c)​

=(a+b+c)( a²+b²+c²-ab-bc-ca)/(a+b+c)

=a²+b²+c²-ab-bc-ca