Question

a^3+b^3+c^3-3abc/ab+bc+ca-a^2-b^2-c.
a=-5
b=-6
c=-10​

Answer 1

Answer:

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Step-by-step explanation:

a^3+b^3+c^3-3abc = (a+b+c)^3

= (-5-6-10)^3 = (-11-10)^3 = (-21)^3 = -9261

[-(a^2+b^2+c^2)+ab+bc+ca] = -1/2 [(a-b)^2+(b-c)^2+(c-a)^2

Using dis formula substitute dis...

Answer 2

Answer:

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