Question

a^3+b^3+c^3-3abc factorise using factor theorem

Answer 1

Answer:

Step-by-step explanation:

 If you put a = -b-c, you can see that the expression is zero.  

(-b-c)^3+b^3+c^3-3(-b-c)bc  

=-b^3-3b^2c-3bc^2-c^3 +b^3+c^3+3b^2c+3bc^2 =0  

So a+b+c is a factor.  

This being cubic adn cyclic in a, b and c, the other factor must be a quadratic and cyclic in a, b and c  

So the factors are (a+b+c)(a^2 + b^2 + c^2 - ab - bc - ca)

Answer 2

Hope it will help you