Question

a^3+b^3-c^3-3abc factorize this one please​

Answer 1

A³ + b³ + c³ -3abc

=a³ + (b³ + c³) -3abc

= a³ + (b +c)³ -3bc(b+c) -3abc

[ given, a+ b + c =0 => b+c = -a put it ]

= a³ + (b+c)³ -3bc(-a) -3abc

= a³ + (b + c)³ +3abc -3abc

[ use, formula , x³ + y³ = (x + y)(x² + y² -xy )

= {a + (b + c)}{a² + (b+c)² -a(b + c)}

=(a + b + c)(a² + b² + c² + 2bc - ab - ac)

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