a^3+b^3+c^3=3abc proved that a=b=c
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Answer:
We know,
a³ + b³ + c³ - 3abc = (a+b+c). (a² + b²c²ab-bc - ca
Putting
a+b+c= 0 on RHS,
we get,
a³ + b³ + c³ 3abc = 0
a³ + b³ + c³ = 3abc,
Hence proved.
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