Math, asked by sayanmondal0123456, 27 days ago

a^3+b^3+c^3=3abc proved that a=b=c​

Answers

Answered by Anonymous
22

Answer:

We know,

a³ + b³ + c³ - 3abc = (a+b+c). (a² + b²c²ab-bc - ca

Putting

a+b+c= 0 on RHS,

we get,

a³ + b³ + c³ 3abc = 0

a³ + b³ + c³ = 3abc,

Hence proved.

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