Question

a^3+b^3+c^3=3adc
so,a+b+c=??

Answer 1

Answer:

$(a+b+c)=0$

Step-by-step explanation:

First of all, you need to know an important identity

$a^3+b^3+c^3-3abc=(a+b+c)(a^2+b^2+c^2-ab-bc-ca)$

From this solve for $a+b+c$

It is only possible for $(a^3+b^3+c^3)$ to be equal to $(3abc)$ when $(a^3+b^3+c^3-3abc=0)$ which is possible only when $(a+b+c=0)$ or $(a^2+b^2+c^2-ab-bc-ca=0)$

So, we conclude that answer.

Hope that helps!....:)