a^3 + b^3 + c^3 = ______
Step by step explanations.
Good Afternoon all.
Answers
Answered by
2
(a+b+c)[a2+b2+c2−ab−bc−ca]+3abc
Answered by
2
Answer:
I hope it will help you please mark me as brainest
Step-by-step explanation:
First method
a3+b3=a3+ab2−a2b+b3+a2b−ab2=a(a2+b2−ab)+b(a2+b2−ab)=(a+b)(a2+b2−ab)
To find a3−b3 , replace b with − b
a3−b3=(a−b)(a2+b2+ab)
Second method
(a+b)3=(a+b)2(a+b)=(a2+2ab+b2)(a+b)=a3+3a2b+3ab2+b3=a3+b3+3ab(a+b)
a3+b3=(a+b)3−3ab(a+b)=(a+b)(a2+b2−ab)
For a3−b3 , replace b with −b
a3−b3=(a−b)3+3ab(a−b)=(a−b)(a2+b2+ab)
Similar questions