Math, asked by anushreebasu197, 11 months ago

a^-3 b^-4/a^-2 b^-3 plz solve this

Answers

Answered by genious2000
0

Answer:

1/ab is the answer.

Step-by-step explanation:

A^-3 b^-4/a^-2 b^-3

= (1/A^3 b^4)/(1/a^2 b^3)

= (a^2 /a^3) (b^3/ b^4)

= a^(2-3) b^(3-4)

= a^-1 b^-1

= 1/ab

Answered by bansil003
0
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