Question

|a|=3,|b|=4 ,|c|=5are perpendicular sum of other two find|a+b+c|

Answer 1

Answer:

${ ( |a| + |b| + |c|) }^{2} = {a}^{2} + {b}^{2} + {c}^{2} \\ \\ = 9 + 16 + 25 = 50 \\ \\ |a| + |b| + |c| = \sqrt{50} = 5 \sqrt{2}$