A=3+b then find the value of a³-b³-9ab
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a=3+b
taking cube on both sides
a^3=27+b^3+27b+9b^2
a^3=27+b^3+9b(3+b)
a^3=b^3+27+9ab
a^3-b^3-9ab=27
hence proved....
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