Question

A 3 by 1.5 cm waveguide is filled with air medium. Calculate the phase velocity for TE_(01) mode at the operating frequency of 12 GHz​

Answer 1

Answer:

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Answer 2

Answer:

Explanation:

For the given TE10 mode, the cut-off frequency will be:

$f_{c}$ = $\frac{c}{2a}$

With a = 7cm (given)

$f_{c}$ = $\frac{3 x 10^{10} }{2 x 7}$ = 2.142 GHz

f = 3.5 GHz

cos θ = $\sqrt{ 1 -\frac{2.142}{3.5} ^{2} }$ = 0.79

$V_{p}$ = $\frac{3 x 10^{2} }{0.79}$= 3.78 x $10^{8}$ m/s

Waves can move in groups called wave packets, and group velocity is the speed at which each wave packet travels. The rate at which a wave's phase travels is known as its phase velocity. Between group velocity and phase velocity, there is a proportionate relationship.