Question

a 3 cm long object is placed at 12 cm from a concave lens perpendicular to its principal Axis the lens from a virtual image whose size is 1.5 cm find the power of the lens

Answer 1

Answer:

4 cm

Explanation:

Distance of object from the mirror, u=−30

Distance of image from the mirror, v=−60 , image is real.

Now we know magnification ratio m=−u/v

m= — −30/−60

m=−2

Height of object h=2cm

Image height h1

=m×h=−2×2=−4cm

Height of image is 4 cm and its inverted .