A 3 cm tall object is placed 18 cm in front of a concave mirror of focal length 12 cm. At what distance from the mirror should a screen be placed to see a sharp image of the object on the screen. Also calculate the height of the image formed.
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Explanation:
Given :-
u = - 18 cm
f = - 12 cm
To Find :-
u = ?
Image Height = ??
Solution :-
Using the mirror formula,
1/f = 1/v + 1/u
⇒ 1/v + 1/- 18 = 1/- 12
⇒ 1/v = - 1/12 + 1/18
⇒ 1/v = (-3 + 2)/36
⇒ 1/v = - 1/36
⇒ v = -36 cm
Magnification, m = - v/u
Also, m = h₁/h₂
⇒ m = - 36/- 18 = - 2
⇒- 2 = h₁/3
⇒ h₁ = - 6 cm
Hence, The image height will be 6 cm.
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