A 3 cm thick iron open box is made whose external dimensions are 78 cm x 54cm x 12cm.Find the weight of the box if its density is 60 gm/cm3.
Answers
Given :
- External Dimensions of open box are 78 cm, 54 cm and 12 cm.
- The thickness of the iron open bow = 3 cm.
To find :
- The weight of the box if its density is 60 gm/cm³ =?
Step-by-step explanation :
It is Given that,
External length of open iron box = 78 cm.
External breadth of open iron box = 54 cm.
External height of open iron box = 12 cm.
Now,
As We know that,
Volume of cuboid = length x breadth x height
Substituting the values in the above formula, we get,
= 78 × 54 × 12
= 50544.
Therefore, External Volume of open iron box = 50544 cm³.
Now,
Internal length of open iron box = 78 - (3 + 3) cm = 72 cm
Similarly,
Internal breadth of open iron box = 54 - 6 cm = 48 cm.
Internal height of open iron box = 12 - 3 cm = 9 cm.
Now,
Similarly as we solve the above case,
= 72 × 48 × 9
= 31104.
Therefore, Internal Volume of open iron box = 31104 cm³.
After that,
Density of open iron box = 50544 cm³ - 31104 cm³ = 19440 cm³
Therefore, the weight of the box if its density is 60 gm/cm³ = 19440 × 60 = 1166.4 kg.
Answer:
1166.4
Step-by-step explanation:
I hope this answer is correct